2X+2H2O =2XOH+H2
n(H2)=8,96/22,4=0,4моль
nX:nH2=2:1
n(X)=0,4*2=0,8моль
M(X)=31,9/0,8=39,25г/моль
X-калий
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
2X+2H2O =2XOH+H2
n(H2)=8,96/22,4=0,4моль
nX:nH2=2:1
n(X)=0,4*2=0,8моль
M(X)=31,9/0,8=39,25г/моль
X-калий