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egivargizova
@egivargizova
June 2022
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Определить число молекул карбон (IV) оксида, содержащихся при нормальных условиях в 11,2 л этого газа.
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lyubavasil
N=V/Vm n(CO2)=11,2/22,4=0,5 моль
N=n*NA N(CO2)=0,5*6,02*1023=3,01*1023(молекул)
Ответ:3,01*1023 молекул
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Answers & Comments
N=n*NA N(CO2)=0,5*6,02*1023=3,01*1023(молекул)
Ответ:3,01*1023 молекул