CnH2n-6 + 3H2 -> CnH2n
n(H2)=6,72/22,4=0,3моль; n(CnH2n-6) = 0,3/3=0,1моль;
M(CnH2n-6)=7,8/0,1=78г/моль;
12n+2n-6=78
14n=84
n=6;
Ответ: С6H6-бензол
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CnH2n-6 + 3H2 -> CnH2n
n(H2)=6,72/22,4=0,3моль; n(CnH2n-6) = 0,3/3=0,1моль;
M(CnH2n-6)=7,8/0,1=78г/моль;
12n+2n-6=78
14n=84
n=6;
Ответ: С6H6-бензол