Home
О нас
Products
Services
Регистрация
Войти
Поиск
Oponent689
@Oponent689
July 2022
1
0
Report
Определить массовые доли элементов в веществе а) HMnO4 б) K2SO3
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
Doc2100
A) M(HMnO4)=120 г/моль
w(H)=1/120=0,01*100%=1%
w(Mn)=55/120=0,46*100%=46%
w(O4)=100%-1%-46%=53%
б)M(K2SO3)=39*2+32+16*3=158
г/моль
w(K2)=78/158=0,49*100%=49%
w(S)=32/158=0,20*100%=20%
w(O3)=100%-49%-20%=31%
4 votes
Thanks 7
More Questions From This User
See All
Oponent689
August 2022 | 0 Ответы
reshite sistemu uravnenijed67739e67da76e271835380567449a1 71587
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Определить массовые доли элементов в веществе а) HMnO4 б) K2SO3..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
w(H)=1/120=0,01*100%=1%
w(Mn)=55/120=0,46*100%=46%
w(O4)=100%-1%-46%=53%
б)M(K2SO3)=39*2+32+16*3=158 г/моль
w(K2)=78/158=0,49*100%=49%
w(S)=32/158=0,20*100%=20%
w(O3)=100%-49%-20%=31%