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aniamanzhos
@aniamanzhos
October 2021
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определить массовые доли химических элементов в ортофосфорной кислоте H3PO4
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vipmaster2011
M(H3PO4)=98г/моль
w((H)= 3:98*100=3,06%
w(P)=31:98*100=31,63%
w(O4)=64:98*100=65,3%
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Answers & Comments
w((H)= 3:98*100=3,06%
w(P)=31:98*100=31,63%
w(O4)=64:98*100=65,3%