Определить массовые доли ( в процентах) химический элементов в карбонате калия ?
K2CO3
W%(k2)=K2*100%/K2CO3=39*2*100%/39*2+12+16*3=7800/138=56,5% (K)
W%(C)=C*100%/K2CO3=12*100%/39*2+12+16*3=1200/138=8,7% (C)
W%(O3)=O3*100%/K2CO3=16*3*100%=39*2+12+16*3=4800/138=34,7%(O3)
Дано По формуле : W=nAr/Mr*100%
K2CO3 Тогда
W(O) - ? W(К)=39*2*100%/39*2+12+16*3=56,5%
W(C) - ? W(C)=12*100%/39*2+12+16*3=8,7%
W(К) - ? W(O)=16*3*100%=39*2+12+16*3=34,7%
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K2CO3
W%(k2)=K2*100%/K2CO3=39*2*100%/39*2+12+16*3=7800/138=56,5% (K)
W%(C)=C*100%/K2CO3=12*100%/39*2+12+16*3=1200/138=8,7% (C)
W%(O3)=O3*100%/K2CO3=16*3*100%=39*2+12+16*3=4800/138=34,7%(O3)
Дано По формуле : W=nAr/Mr*100%
K2CO3 Тогда
W(O) - ? W(К)=39*2*100%/39*2+12+16*3=56,5%
W(C) - ? W(C)=12*100%/39*2+12+16*3=8,7%
W(К) - ? W(O)=16*3*100%=39*2+12+16*3=34,7%