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Ира2807
@Ира2807
July 2022
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Определить массу соли,полученной в результате взаимодействия 4,7г фенола с 6г раствора NaOH
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Alexei78
Дано
m(C6H5OH) = 4.7 g
m(NaOH) = 6 g
---------------------------
m(C6H5ONa)-?
M(C6H5OH) = 94 g/mol
n(C6H5OH) = m/M = 4.7 / 94 = 0.05 mol
M(NaOH) = 40 g/mol
n(NaOH) = m/M = 6/40 = 0.15mol
n(C6H5OH) < n(NaOH)
M(C6H5ONa) = 116 g/mol
C6H5OH+NaOH-->C6H5ONa+H2O
n(C6H5OH) = n(C6H5ONa) = 0.05 mol
m(C6H5ONa) = n*M = 0.05*116 = 5.8 g
ответ 5.8 г
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Answers & Comments
m(C6H5OH) = 4.7 g
m(NaOH) = 6 g
---------------------------
m(C6H5ONa)-?
M(C6H5OH) = 94 g/mol
n(C6H5OH) = m/M = 4.7 / 94 = 0.05 mol
M(NaOH) = 40 g/mol
n(NaOH) = m/M = 6/40 = 0.15mol
n(C6H5OH) < n(NaOH)
M(C6H5ONa) = 116 g/mol
C6H5OH+NaOH-->C6H5ONa+H2O
n(C6H5OH) = n(C6H5ONa) = 0.05 mol
m(C6H5ONa) = n*M = 0.05*116 = 5.8 g
ответ 5.8 г