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time1387
@time1387
July 2022
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определить объем ,который занимает HF при н.у массой 40г
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alima1958
Verified answer
M(HF)=20г/моль 20гHF ------22,4л x=40*22.4/20=44.8л
40гHF--------хл
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Verified answer
M(HF)=20г/моль 20гHF ------22,4л x=40*22.4/20=44.8л40гHF--------хл