6HCl+2Al=2AlCl3+3H2
n(Al)=40*0.05:27=0.074 моль
n(H2)=0.074:2*3=0.111 моль
V=0.111*22.4=2.49л
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
6HCl+2Al=2AlCl3+3H2
n(Al)=40*0.05:27=0.074 моль
n(H2)=0.074:2*3=0.111 моль
V=0.111*22.4=2.49л