2MgCO3+4HNO3=2Mg(NO3)2+2CO2+2H2O
m (MgCO3)=127.3*71/100=90.4
V (CO2)=90.4*44.8/168=24 л
Ответ 24 литров
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2MgCO3+4HNO3=2Mg(NO3)2+2CO2+2H2O
m (MgCO3)=127.3*71/100=90.4
V (CO2)=90.4*44.8/168=24 л
Ответ 24 литров