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uporova2013
@uporova2013
November 2021
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определить состав и формулу циклоалкана, у которого плотность по воздуху 1,449
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lyubavasil
Mr=29*1,449=42
Mr(CnH2n)=14n
14n=42 n=3
C3H6 -циклопропан
2 votes
Thanks 1
uporova2013
огромное спасибо!
lyubavasil
нз
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Answers & Comments
Mr(CnH2n)=14n
14n=42 n=3
C3H6 -циклопропан