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Sonya336
@Sonya336
July 2022
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Определить значения b, при которых одним из корней уравнения 8x^2+(2b+1)x+2b-1=0 является число b
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8x^2+(2b+1)x+2b-1=0
8b^2+(2b+1)b+2b-1=0
8b^2+2b^2+b+2b-1=0
10b^2+3b-1=0
D=9-4*10*(-1)=9+40=49
b=(-3-7)/20=-1/2
b=(-3+7)/20=4/20=0.2
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Answers & Comments
8b^2+(2b+1)b+2b-1=0
8b^2+2b^2+b+2b-1=0
10b^2+3b-1=0
D=9-4*10*(-1)=9+40=49
b=(-3-7)/20=-1/2
b=(-3+7)/20=4/20=0.2