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Sofahgf
@Sofahgf
July 2022
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Определите химическую формулу , имеющую следующий состав : углерод - 36 % водорода - 13 % кислорода - 51 %
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krioira
X:Y:Z = 0.36/12 : 0.13/1: 0.51/16
X:Y:Z = 0.03 : 0.13 : 0.03
X:Y:Z = 1: 4 : 1
Формула: СН4О
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Answers & Comments
X:Y:Z = 0.03 : 0.13 : 0.03
X:Y:Z = 1: 4 : 1
Формула: СН4О