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180203kga
@180203kga
August 2022
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Определите количество вещества в а)12,04*10^23 атомов железа
б)3.01*10^23 атомов водорода в) 6,02*10^23 атомов углерода
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Stronghold
A)
N = 12.04 * 10²³
NA = 6.02 * 10²³
γ = N / NA = 12.04 * 10²³ / 6.02 * 10²³ = 2.02 моль
б)
N = 3.01 * 10²³
NA = 6.02 * 10²³
γ = N / NA = 3.01 * 10²³ /
6.02 * 10²³ = 0.5 моль
в)
N = 6.02 * 10²³
NA = 6.02 * 10²³
γ = N / NA = 6.02 * 10²³ /
6.02 * 10²³ = 1 моль
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180203kga
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opredelite kolichestvo veshestva v a12041023 atomov zheleza b3011023 atomov4f399da2122a191619aad196e0d163b6 89946
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Answers & Comments
N = 12.04 * 10²³
NA = 6.02 * 10²³
γ = N / NA = 12.04 * 10²³ / 6.02 * 10²³ = 2.02 моль
б)
N = 3.01 * 10²³
NA = 6.02 * 10²³
γ = N / NA = 3.01 * 10²³ / 6.02 * 10²³ = 0.5 моль
в)
N = 6.02 * 10²³
NA = 6.02 * 10²³
γ = N / NA = 6.02 * 10²³ / 6.02 * 10²³ = 1 моль