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Villkozz
@Villkozz
August 2021
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определите массовую доли элемента Al(OH)3
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krioira
Mr(Al(OH)3)=27+3*16+3*1=78
W(Al)=27/78=0.34=34%
W(O)=48/78=0.62=62%
W(H)=3/78=0.04=4%
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Answers & Comments
W(Al)=27/78=0.34=34%
W(O)=48/78=0.62=62%
W(H)=3/78=0.04=4%