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Виктория0276
@Виктория0276
August 2021
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определите массовую долю элементов:
1)Na2O
2)K3PO4
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Answers & Comments
koka11
1. Na2O = (23*2+16) = 62,
w (Na2) = 46/62 = 0, 7419 (74,2 %)
w (O) = 16/62 = 0, 258 (25,8 %)
2. K3PO4 = (39*3 + 31 + 16*4) = 212,
w (K3) = 117/212 = 0,552 (55,2 %)
w (P) = 31/212 = 0, 1462 (14,62 %)
w (O4) = 64/212 = 0,3019 (30, 19 %).
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Answers & Comments
1. Na2O = (23*2+16) = 62,
w (Na2) = 46/62 = 0, 7419 (74,2 %)
w (O) = 16/62 = 0, 258 (25,8 %)
2. K3PO4 = (39*3 + 31 + 16*4) = 212,
w (K3) = 117/212 = 0,552 (55,2 %)
w (P) = 31/212 = 0, 1462 (14,62 %)
w (O4) = 64/212 = 0,3019 (30, 19 %).