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Scissorluv0102
@Scissorluv0102
August 2022
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Определите массовую долю хлора в соединении HClO3
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Darkness21
M(HClO3) = 1+35,5+48=84,5
массовая доля хлора = 35,5/84,5= 0,42; 42%
4 votes
Thanks 6
sarvinoz
HCLO3=1+35.5+48=84.5
W=35.5/84.5*100%=42%
1 votes
Thanks 2
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Answers & Comments
массовая доля хлора = 35,5/84,5= 0,42; 42%
W=35.5/84.5*100%=42%