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belyaeva21
@belyaeva21
July 2022
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Определите массовую долю в % каждого элемента в следующем соединение Mr(Fe(HSO3)2)
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irishekova
Verified answer
Mr(Fe(HSO3)2)=56+2*(1+32+48)=218
w(Fe)=56/218=0.26*100%=26%
w(H)=2/218=0.009*100%=0.9%
w(S)=64/218=0.29*100%=29%
w(O)=100%-26%-0.9%-29%=44.1%
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Answers & Comments
Verified answer
Mr(Fe(HSO3)2)=56+2*(1+32+48)=218w(Fe)=56/218=0.26*100%=26%
w(H)=2/218=0.009*100%=0.9%
w(S)=64/218=0.29*100%=29%
w(O)=100%-26%-0.9%-29%=44.1%