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Villkozz
@Villkozz
July 2022
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Определите массовые доли элементов Fe(Oн)2
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allahakobyan20
Mr(Fe(OH)2)=56+16*2+1*2=56+32+2=90
W(Fe)=Ar*n/Mr*100℅=56*1/90=62,22%
W(O)=16*2/90*100%=35,55%
W(H)=1*2/90*100%=2,22%
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Villkozz
спасибо выручил )
allahakobyan20
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Answers & Comments
W(Fe)=Ar*n/Mr*100℅=56*1/90=62,22%
W(O)=16*2/90*100%=35,55%
W(H)=1*2/90*100%=2,22%