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denisden4ikiv
@denisden4ikiv
July 2022
1
6
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Определите массовые доли
элементов в HNO
3
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evgenia542
HNO3= 1*1+1*14+3*116+63
W(H)=1\63*100%=1,6%
W(N)=14\63*100%=22,2%
W(0)= 3*16\63*100%76,2%
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Answers & Comments
W(H)=1\63*100%=1,6%
W(N)=14\63*100%=22,2%
W(0)= 3*16\63*100%76,2%