KClO3 = 122.5 г/моль
w(K) - (39 ÷ 122,5) × 100% = 32%
w(Cl) = (35,5 ÷ 122,5) × 100% = 29%
w(O) = (16×3 ÷ 122,5) × 100% = 39%
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Verified answer
KClO3 = 122.5 г/моль
w(K) - (39 ÷ 122,5) × 100% = 32%
w(Cl) = (35,5 ÷ 122,5) × 100% = 29%
w(O) = (16×3 ÷ 122,5) × 100% = 39%