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Chopadjda
@Chopadjda
August 2022
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Определите массу 3*10^23 молекул бромоводорода
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Вoлхв
Формула бромоводорода --HBr.Воспользуемся формулами:v=N/6,02*10^23; v=m/M.1)M(HBr)=1+80=81 г/моль.2)v(HBr)=3*10^23/6,02*10^23=0,5 моль3)m(HBr)=81*0,5=40,5 гОтвет:m(HBr)=40,5 гПерепроверь!
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