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November 2021
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определите массу 5,6 л (н.у) NO2
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MadiKey
Моль(NO2)=5,6/22,4=0,25
Масса=0,25•46=11,5г
0 votes
Thanks 5
Odarka10
Дано
V(NO2)=5,6 л
n=V:Vm=5,6:22,4=0,25моль
n=m:M
M(NO2)=14+32=46
m=0,25•46=11,5
3 votes
Thanks 6
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Answers & Comments
Масса=0,25•46=11,5г
V(NO2)=5,6 л
n=V:Vm=5,6:22,4=0,25моль
n=m:M
M(NO2)=14+32=46
m=0,25•46=11,5