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nikitinroman20
@nikitinroman20
March 2022
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определите массу алюмината натрия полученного при взаимодействии гидроксида алюминия с 200 граммами NAOH
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nikitokkk
NaOH+Al(OH)3=NaAlO2+2H2O
n(NaOH)=200/40=5 моль
m(NaAlO2)=5*82=410 г
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Answers & Comments
n(NaOH)=200/40=5 моль
m(NaAlO2)=5*82=410 г