Verified answer

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Verified answer

дано

mтехн(KNO3) =150 g

W(прим) = 10%

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m(HNO3)-?

mчист(KNO3) = 150 - (150*10%/100%) = 135 g

2KNO3+H2SO4-->K2SO4+2HNO3

M(KNO3)= 101 g/mol

n(KNO3)= m/M = 135/101= 1.33 mol

2n(KNO3) = 2n(HNO3) = 1.33 mol

M(HNO3) = 63 g/mol

m(HNO3) = n*M = 1.33 * 63 = 83.79 g

ответ 83.79 г

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