Ответ:
дано
m(KOH) = 28 g
-----------------
m(KCO3) - ?
2KOH+CO2-->K2CO3+H2O
M(KOH) = 56 g/mo
n(KOH) = m/M =28 / 56 = 0.5 mol
2n(KOH) = n(K2CO3)
n(K2CO3) = 0.5 /2 = 0.25 mol
M(K2CO3) = 138g/mol
m(K2CO3) = n*M = 0.25 * 138 = 34.5 g
ответ 34.5 гр
Объяснение:
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Verified answer
Ответ:
дано
m(KOH) = 28 g
-----------------
m(KCO3) - ?
2KOH+CO2-->K2CO3+H2O
M(KOH) = 56 g/mo
n(KOH) = m/M =28 / 56 = 0.5 mol
2n(KOH) = n(K2CO3)
n(K2CO3) = 0.5 /2 = 0.25 mol
M(K2CO3) = 138g/mol
m(K2CO3) = n*M = 0.25 * 138 = 34.5 g
ответ 34.5 гр
Объяснение: