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kristinakuts20
@kristinakuts20
November 2021
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Определите массу купрум (2) оксида, которая образуется при взаимодействии меди массой 6.42 с кислородом массой 1.62
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ndambaeva
VCu=6.42.128=0.05mol
vO2=1.62/32=0.05mol
vCu=vO=0.05mol
1.62g xg
2Cu+O2=2CuO
32g 160g
x=1.62·160/32=8.1g
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Answers & Comments
vO2=1.62/32=0.05mol
vCu=vO=0.05mol
1.62g xg
2Cu+O2=2CuO
32g 160g
x=1.62·160/32=8.1g