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Sasha0307
@Sasha0307
July 2022
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Определите массу осадка которая образуется 300 г 10% раствора CaOH с CO2
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Alexei78
Дано
m(ppa Ca(OH)2) = 300 g
W(Ca(OH)2)= 10%
+CO2
---------------------
m(CaCO3)-?
m(Ca(OH)2) = 300*10%/100% = 30 g
30 X
Ca(OH)2+CO2-->CaCO3+H2O
74 100
M(Ca(OH)2) = 74 g/mol M(CaCO3) =100 g/mol
X=30*100 / 74 = 40.54 g
ответ 40.54 г
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Sasha0307
А осадок это разве не H2O
Sasha0307
???
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Answers & Comments
m(ppa Ca(OH)2) = 300 g
W(Ca(OH)2)= 10%
+CO2
---------------------
m(CaCO3)-?
m(Ca(OH)2) = 300*10%/100% = 30 g
30 X
Ca(OH)2+CO2-->CaCO3+H2O
74 100
M(Ca(OH)2) = 74 g/mol M(CaCO3) =100 g/mol
X=30*100 / 74 = 40.54 g
ответ 40.54 г