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xdezzly
@xdezzly
May 2021
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определите массу соли образованную в нейтрализации 600 г 20% соляной кислоты гидроксидом калия
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trserg
Verified answer
HCl + KOH = KCl + H2O
1моль 1 моль
m(HCl) = 600*0.2 = 120г
n(HCl) = 120/36.5=3.29 моль
n(KCl) = n(HCl) = 3.29моль
m(KCl)=n*M = 3.29 * 74.5 = 245.1г
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Verified answer
HCl + KOH = KCl + H2O1моль 1 моль
m(HCl) = 600*0.2 = 120г
n(HCl) = 120/36.5=3.29 моль
n(KCl) = n(HCl) = 3.29моль
m(KCl)=n*M = 3.29 * 74.5 = 245.1г