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artemich7
@artemich7
July 2022
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Определите массу железа,необходимую для реакции с 4 г. серы.(9 класс)
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simona6432
Fe + S = FeS
n(Fe) = n(S)
n(S) = 4/32 = 0,125 моль
m(Fe) = n * M(Fe) = 0,125 моль* 56 г/моль = 7 г.
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Answers & Comments
n(Fe) = n(S)
n(S) = 4/32 = 0,125 моль
m(Fe) = n * M(Fe) = 0,125 моль* 56 г/моль = 7 г.