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karinashakhovaKs
@karinashakhovaKs
June 2022
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определите молекулярную формулу соединения, если плотность паров вещества по водороду 22,5, а массовые доли C-0,535; H-0,155; N-0,312
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Scorpeon
M(CxHyNz) = D(H₂)*M(H₂) = 22.5*2г/моль = 45 г/моль
Z(C) = 0.535*45/12 = 2
Z(H) = 0.155*45/1 = 7
Z(N) = 0.312*45/14 = 1
C₂H₇N
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Answers & Comments
Z(C) = 0.535*45/12 = 2
Z(H) = 0.155*45/1 = 7
Z(N) = 0.312*45/14 = 1
C₂H₇N