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Wah11
@Wah11
October 2021
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Определите моляльную концентрацию 513 грамм 20 %ного раствора Al2(SO4)3
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6opcy4OK
Найдем массу Al2(SO4)3:
m=513*0,2=102,6г
1моль-342г
Хмоль-102,6г
х=1*102,6/342=0,3
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Answers & Comments
m=513*0,2=102,6г
1моль-342г
Хмоль-102,6г
х=1*102,6/342=0,3