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barsukova517
@barsukova517
November 2021
2
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Определите на каком расстоянии от поверхности земли сила притяжения космического коробля конец уменьшится в 121 раз
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fatt52
Verified answer
F1/F2=121
h=?
======
F1=G*m*M/R²
F2=G*m*M/(R+h)²
√(F1/F2)=(R+h)/R=√121=11
h=10R
==================
1 votes
Thanks 1
MashaPutnaj
Verified answer
Дано F1/F2=121
F=G*m*M/(R+h)^2
F1/F2=(R+h)^2/R^2=121
(R+h)/R=11
h=10*R=6400*10=64000 км
3 votes
Thanks 3
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Answers & Comments
Verified answer
F1/F2=121h=?
======
F1=G*m*M/R²
F2=G*m*M/(R+h)²
√(F1/F2)=(R+h)/R=√121=11
h=10R
==================
Verified answer
Дано F1/F2=121F=G*m*M/(R+h)^2
F1/F2=(R+h)^2/R^2=121
(R+h)/R=11
h=10*R=6400*10=64000 км