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70Dasha07
@70Dasha07
December 2021
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Определите объем кислорода (н.у), необходимого для реакции с 5,6 г алюминия
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naugros
5.6 хл
4Al + 3O2=2Al2O3
4*27 3*22,4
108 67,2
5,6--------------------------хл
108------------------------67,2
х=5,6*67,2/108=3,48 л
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Answers & Comments
5.6 хл
4Al + 3O2=2Al2O3
4*27 3*22,4
108 67,2
5,6--------------------------хл
108------------------------67,2
х=5,6*67,2/108=3,48 л