2Al+6HCl= 2AlCl3+3H2
33.75 гр × 67.2л / 54гр (Al)= 42 л
Ответ: Н2 - 42л
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2Al+6HCl= 2AlCl3+3H2
33.75 гр × 67.2л / 54гр (Al)= 42 л
Ответ: Н2 - 42л