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July 2022
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Определите процентную концентрацию раствора бромида калия, если к 450г 3-процентного раствора добавили 7г бромида.
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mrvladimir2
Verified answer
M'(KBr) = m'(p-pa KBr)*ω'(KBr)
m'(KBr) = 450 г*3/100 = 13,5 г
m"(KBr) = m'(KBr)+m(KBr)
m"(KBr) = 13,5 г + 7 г = 20,5 г
m"(p-pa KBr) = m'(p-pa KBr) + m(KBr)
m"(p-pa KBr) = 450 г + 7 г = 457 г
ω"(KBr) = m"(KBr)/m"(p-pa KBr)*100%
ω'(KBr) = 20,5 г/457 г*100% = 4,49%≈4,5%
Ответ: 4,5%
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Answers & Comments
Verified answer
M'(KBr) = m'(p-pa KBr)*ω'(KBr)m'(KBr) = 450 г*3/100 = 13,5 г
m"(KBr) = m'(KBr)+m(KBr)
m"(KBr) = 13,5 г + 7 г = 20,5 г
m"(p-pa KBr) = m'(p-pa KBr) + m(KBr)
m"(p-pa KBr) = 450 г + 7 г = 457 г
ω"(KBr) = m"(KBr)/m"(p-pa KBr)*100%
ω'(KBr) = 20,5 г/457 г*100% = 4,49%≈4,5%
Ответ: 4,5%