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AnastasiaA9
@AnastasiaA9
October 2021
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Определите суммарное число электронов в составе молекул:
HNO3
H2SO4
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serkina1971
Verified answer
HNO3
H=1
N=7
0=8*3=24
1+7+24=32
H2SO4
H=1*2
S=16
O=8*4=32
2+16+32=50
5 votes
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Answers & Comments
Verified answer
HNO3H=1
N=7
0=8*3=24
1+7+24=32
H2SO4
H=1*2
S=16
O=8*4=32
2+16+32=50