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1236lkjg
@1236lkjg
July 2022
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Определите все "а", если при каждом из которых уравнение
sin^2x - 4sinxcosx + a cos^2x=0 не имеет решения.
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sedinalana
Verified answer
Sin^2x - 4sinxcosx + a cos^2x=0/cos²x
tg²x+4tgx+a=0
tgx=m
m²+4m+a=0
D=16-4a<0
4a>16
a>4
a∈(4;∞)
4 votes
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Answers & Comments
Verified answer
Sin^2x - 4sinxcosx + a cos^2x=0/cos²xtg²x+4tgx+a=0
tgx=m
m²+4m+a=0
D=16-4a<0
4a>16
a>4
a∈(4;∞)