Определите,какое кол-во теплоты необходимо для превращения 200 гр льда при t=-10...

1971l @1971l

July 2022 1 3 Report

Определите,какое кол-во теплоты необходимо для превращения 200 гр льда при t=-10 градусов в воду,при t=20 градусов.

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Дано:
$m=200g$
$t_1^o=-10^oC$
$t_2^o=0^oC$
$C=2100 \frac{Dg}{kg*^oC}$
λ $=340000 \frac{Dg}{kg}$
$-----$
$Q-?$

Решение:
$Q=Q_1+Q_2$
$Q_1=Cm(t_2^o-t^o_1)$
$Q_2=-$ λ $m$
$m=200g=0,2kg$
$Q_1=2100 \frac{Dg}{kg*^oC}*0,2kg*(-10^oC-0^oC)=-4200Dg$
$Q_2=-340000 \frac{Dg}{kg}*0,2kg=-68000Dg$
$Q=-4200Dg+(-68000Dg)=-72200Dg=-72,2kDg$

Ответ: $Q=-72,2kDg$

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