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jeka2701
@jeka2701
July 2022
1
10
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опредилите объем (н.у) 3 моль H2
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irau8640
3 моль H2 = 3V H2
V(H2)=3моль*22,4л/моль=67,2л
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Answers & Comments
3 моль H2 = 3V H2
V(H2)=3моль*22,4л/моль=67,2л