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Anita17032002
@Anita17032002
July 2022
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Осуществить цепочки превращений. Реакции ионного обмена записать в молекулярном,
полном ионном и сокращенном ионном видах.
Fe → FeCl2 → FeCl3 → Fe(OH)3 → Fe2O3 → Fe2(SO4)3 → BaSO4
Al2O3 ← Al(NO3)3 ← Al → Al2O3 → AlBr3 → AgBr
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Answers & Comments
SLI2000a
1) Fe + 2HCl = FeCl2 + H2
2) 2FeCl2 + Cl2 = 2FeCl3
3) FeCl3 + 3NaOH = 3NaCl + Fe(OH)3
4) 2Fe(OH)3 = Fe2O3 + 3H2O
5) Fe2O3 + 3H2SO4 = Fe2(SO4)3 + 3H2O
6) Fe2(SO4)3 + 3BaCl2 = 3BaSO4 + 2FeCl3
1) Al + 6HNO3(конц) = Al(NO3)3 + 3NO2 + 3H2O
2) 4Al(NO3)3 = 2Al2O3 + 12NO2 + 3O2
3) Al2O3 + 6HBr = 2AlBr3 + 3H2O
4) AlBr3 + 3AgNO3 = 3AgBr + Al(NO3)3
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Answers & Comments
2) 2FeCl2 + Cl2 = 2FeCl3
3) FeCl3 + 3NaOH = 3NaCl + Fe(OH)3
4) 2Fe(OH)3 = Fe2O3 + 3H2O
5) Fe2O3 + 3H2SO4 = Fe2(SO4)3 + 3H2O
6) Fe2(SO4)3 + 3BaCl2 = 3BaSO4 + 2FeCl3
1) Al + 6HNO3(конц) = Al(NO3)3 + 3NO2 + 3H2O
2) 4Al(NO3)3 = 2Al2O3 + 12NO2 + 3O2
3) Al2O3 + 6HBr = 2AlBr3 + 3H2O
4) AlBr3 + 3AgNO3 = 3AgBr + Al(NO3)3