освободмтест от иррациональности в знаменателе дроби. Created by Americanec. algebra-ru

освободмтест от иррациональности в знаменателе дроби...

Americanec @Americanec

July 2022 1 3 Report

освободмтест от иррациональности в знаменателе дроби

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Mihail001192

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$\frac{19}{2 \sqrt{5} - 1} = \frac{19 \times (2 \sqrt{5} + 1)}{(2 \sqrt{5} - 1)(2 \sqrt{5} + 1)} = \frac{19 \times (2 \sqrt{5} + 1) }{ {(2 \sqrt{5} )}^{2} - {1}^{2} } = \\ \\ = \frac{19 \times (2 \sqrt{5} + 1)}{20 - 1} = 2 \sqrt{5} + 1 \\ \\$

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Americanec July 2022 | 0 Ответы

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Americanec July 2022 | 0 Ответы

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Americanec July 2022 | 0 Ответы

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Americanec December 2021 | 0 Ответы

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