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korothemmkova20
@korothemmkova20
November 2021
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ОТДАЮ ПОСЛЕДНИЕ БАЛЛЫ
записать химические уравнения, минимально 5
Фтор
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Хлор
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Бром
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Йод
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Max0549
Фтор:
H2+F2=2HF
2H2O+2F2=4HF+02
Xe+2F2=XeF4
2Na+F2=2NaF
2KBr+F2=Br2+2KF
Хлор:
2=2+2
2+2=2
+2=2+2
+=2+
+=
Бром:
Na2SO3 + Br2 + H2O = Na2SO4 + 2HBr
BaS + 4Br2 + 4H2O = BaSO4 + 8HBr
5Cl2 + Br2 + 6H2O = 2HBrO3 + 10HCl
BrF5+3H2O=HBrO3+5HF
2Fe+3Br2=2FeBr3
Йод:
H2+I2=2HI
Hg+I2=HgI2
I2+H2O=HI+HIO
Kl+I2=KI3
2Al+3I2=2Al I3
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Answers & Comments
H2+F2=2HF
2H2O+2F2=4HF+02
Xe+2F2=XeF4
2Na+F2=2NaF
2KBr+F2=Br2+2KF
Хлор:
2=2+2
2+2=2
+2=2+2
+=2+
+=
Бром:
Na2SO3 + Br2 + H2O = Na2SO4 + 2HBr
BaS + 4Br2 + 4H2O = BaSO4 + 8HBr
5Cl2 + Br2 + 6H2O = 2HBrO3 + 10HCl
BrF5+3H2O=HBrO3+5HF
2Fe+3Br2=2FeBr3
Йод:
H2+I2=2HI
Hg+I2=HgI2
I2+H2O=HI+HIO
Kl+I2=KI3
2Al+3I2=2Al I3