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mioilakha
@mioilakha
July 2022
1
6
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Отношение корней квадратного уравнения 8x в квадрате +bx+6=0 равно 3. Найдите b.
A) ±16
В) ±0.75
C) ±12
D) ±1
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sedinalana
Verified answer
8x²+bx+6=0
b/8=-(x1+x2)⇒b=-8(x1+x2)
x1/x2=3
x1=3x2
x1*x2=6/8
3x²*x2=3/4
3x2²=3/4
x2²=1/4
x2=-1/2⇒x1=-3/2⇒b=-8(-1/2-3/2)=16
x2=1/2⇒x1=3/2⇒b=-8(1/2+3/2)=-16
Ответ А
5 votes
Thanks 9
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Answers & Comments
Verified answer
8x²+bx+6=0b/8=-(x1+x2)⇒b=-8(x1+x2)
x1/x2=3
x1=3x2
x1*x2=6/8
3x²*x2=3/4
3x2²=3/4
x2²=1/4
x2=-1/2⇒x1=-3/2⇒b=-8(-1/2-3/2)=16
x2=1/2⇒x1=3/2⇒b=-8(1/2+3/2)=-16
Ответ А