отношение корней квадратного уравнения xx+2x+q=0 равно 6 .Найдите корни уравнения и значение q
по т.Виета
x1 * x2 = q
x1 + x2 = -2
x1 / x2 = 6 => x1 = 6*x2
6*x2 + x2 = -2 => 7*x2 = -2 => x2 = -2/7
x1 = 6*x2 = 6*(-2/7) = -12/7
q = x1 * x2 = -12/7 * (-2/7) = 24/49
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Verified answer
по т.Виета
x1 * x2 = q
x1 + x2 = -2
x1 / x2 = 6 => x1 = 6*x2
6*x2 + x2 = -2 => 7*x2 = -2 => x2 = -2/7
x1 = 6*x2 = 6*(-2/7) = -12/7
q = x1 * x2 = -12/7 * (-2/7) = 24/49