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Ayanne1
@Ayanne1
July 2022
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Отпределите энергию фотона в Эв длина волны которого 500 нм
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fatt52
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E=h*c/л=6,6*10^-34*3*10^8/(500*10^-9)=4*10^-19=2.5 эВ
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E=h*c/л=6,6*10^-34*3*10^8/(500*10^-9)=4*10^-19=2.5 эВ