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sania132009o
@sania132009o
June 2022
1
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даю 99 б..
помогите решить и понять вот эти примеры: 4(а+5)²-(4a²+40a)/
(p+3)(p-11)+(p+6)²
псс 7 класс
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Answers & Comments
granny23
Не решить, а преобразовать
1)
=4(a^2+2*a*5+5^2) - 4a^2-40a = 4(a^2 +10a+25) - 4a^2-40a = 4a^2+40a+100-
-4a^2-40a= 100
2)
= p*p+3*p-11*p-3*11+p^2+2*p*6+6^2=p^2+3p-11p-33+p^2+12p+36=
=2p^2+4p+3 = 2p(p+2) +3
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Answers & Comments
1)
=4(a^2+2*a*5+5^2) - 4a^2-40a = 4(a^2 +10a+25) - 4a^2-40a = 4a^2+40a+100-
-4a^2-40a= 100
2)
= p*p+3*p-11*p-3*11+p^2+2*p*6+6^2=p^2+3p-11p-33+p^2+12p+36=
=2p^2+4p+3 = 2p(p+2) +3