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nhhngfnb
@nhhngfnb
July 2022
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Переобразуйте левую часть уравнения с помощью формуы двойного угла , а затем решите его
4sinx*cosx=-1
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nKrynka
Решение
4sinx*cosx=-1
2*2sinx*cosx=-1
2sin2x = - 1
sin2x = - 1/2
2x = (-1)^n arcsin(-1/2) +
πk, k ∈
z
2x = (-1)^(n+1) arcsin(1/2) + πk, k ∈ z
2x = (-1)^(n+1) (π/6) + πk, k ∈
z
x = (-1)^(n+1) (π/12) + πk/2, k ∈
z
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Answers & Comments
4sinx*cosx=-1
2*2sinx*cosx=-1
2sin2x = - 1
sin2x = - 1/2
2x = (-1)^n arcsin(-1/2) + πk, k ∈ z
2x = (-1)^(n+1) arcsin(1/2) + πk, k ∈ z
2x = (-1)^(n+1) (π/6) + πk, k ∈ z
x = (-1)^(n+1) (π/12) + πk/2, k ∈ z