D = (-10)2 - 4·1·24 = 100 - 96 = 4
b1 = (10 - √4)/2·1 = 4
b2 = (10 + √4)2·1 = 122 = 6
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P = 2(a+b)
S = a*b
получили систему уравнений
20 = 2(a+b)
24 = ab
10 = a+b
24 = ab
a = 10-b
24 = b(10-b)
24 = 10b - b^2
b^2 -10b +24 = 0
D = (-10)2 - 4·1·24 = 100 - 96 = 4
b1 = (10 - √4)/2·1 = 4
b2 = (10 + √4)2·1 = 122 = 6
a = 10 -ba1 = 10 -4 = 6
a2 = 10 -6 = 4
Стороны прямоугольника 4 и 6 см
с - диагональ
с² = a² +b²
c² = 6² + 4²
c² = 64 + 16 = 100
c = 10 cм