периметр прямоугольника равен 14 см,а площадь 12 см2.Найдите стороны прямоугольника
P=14cm
S=12cm^2
{2(a+b)=14 {a+b=7 {a=7-b {a=7-b {b^2-7b+12=0 {b1=3
{a*b=12 {a*b=12 {b(7-b)=12 {7b-b^2=12 {a=7-b { b2=4
a=7-b
1) {b1=3 2) {b2=4
{a1=4 {a2=3
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P=14cm
S=12cm^2
{2(a+b)=14 {a+b=7 {a=7-b {a=7-b {b^2-7b+12=0 {b1=3
{a*b=12 {a*b=12 {b(7-b)=12 {7b-b^2=12 {a=7-b { b2=4
a=7-b
1) {b1=3 2) {b2=4
{a1=4 {a2=3